4.4. Organigramme de programme :
Entré de données
géométriques du canal et les conditions initiales
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Lecture des données
Calcul des propriétés thermo-physiques
du fluide à l'état de saturation pour la
pression P.
j = 1
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l'état de saturation : P, TSAT, VF, VG,
CpF, CpG, HF, HG, KL, KG,
Impression des propriétés thermo-physiques
du fluide à
ìL, ìG
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A
G (J) = 100 + (j-1) * 100
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Calcul des propriétés thermo-hydrauliques
à la vitesse G (J) : ReL, PrL, ReyL et hFC.
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1
N = 1
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B
N = N + 1
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ÖW (N) =100 + (N-1)×100
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K = K+1
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C
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K = 1
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Z (K) = Z0 + (K -- 1) × n
n : Le pas (n = 0.01) [m]
Calcul de ÖONB (J, K)
0w(N) > 00NB(J,K)
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Oui Non
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Existence du régime diphasique
Transfert en convection forcée simple phase
liquide
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Calcul les cotes des differences regions :
znb(J, N), zFDB(J, N) et z(J, N)
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3
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2
Calcul des propriétés thermo-physiques
du l'eau et sa vapeur à la cote Z(K) du canal pour la pression
P. HFZ, HGZ, TFZ, VFZ, VGZ, SIGMAZ, visfz,
Calcul des propriétés thermo-physiques
du l'eau à la cote Z(K) du canal pour la pression P. HFZ, TFZ,
VGZ, SIGMAZ, visfz ,....
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4
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5
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Region I (monophasique)
Même procedure que simple
h
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Calcul HFC (J, N, K) (Par la correlation
de Bittus Boeter)
Z(K) > Znb(J, N )
Oui Non
Region II (diphasique)
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Tw(N ) *
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~~, ~~, Rf , f, ...
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Tw(J, N ,K) *
(I) * (I) * (I)* + (I) * (DW EI) *
fc e tc tcEs1
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(DW (J, N ) * = (DW (N )
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Oui
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Non
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6
Tw(N ) = Tw(J, N ) *
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5 6
Impression des résultats:
znbE(J, N), zFDB
(J, N) et zsc(J, N)
TW (J, N, K), h_Yeoh (J, N, K).
Impression des résultats:
znb(J, N), zFDB(J, N) et
zsc(J, N)
TW (J, N, K), Hfc (J, N, K).
Impression des résultats: TW (J, N, K), HFC
(J, N, K).
C
Non
Z() Zsc. (J, N)
Oui
B
N = 6
Non
A
Oui
Non
J = 12
Oui
Fin
Figure 4-4 : Organigramme du programme
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